Amphoteric Nature
Amphoteric substances react with both acids and bases, acting as acids with bases (accepting OH⁻) and as bases with acids (donating OH⁻ or accepting H⁺). Aluminium, zinc, and lead (to a lesser extent) exhibit this property in their metals, oxides, and hydroxides.
Summary
- Aluminium: Metal, oxide, and hydroxide react readily with NaOH (forming aluminates) and HCl (forming chlorides), showing strong amphoterism.
- Zinc: Similar to aluminium, forms zincates with NaOH and chlorides with HCl, though metal requires concentrated alkali.
- Lead: Oxide and hydroxide are amphoteric, forming plumbites with NaOH and chlorides with HCl; metal is less reactive with NaOH.
-------------------------------------------------
DETAILS
1. Aluminium (Al)
Aluminium Metal
- With NaOH: Reacts to form sodium aluminate and hydrogen gas:
2Al(s)+2NaOH(aq)+6H2O(l)→2NaAl(OH)4(aq)+3H2(g)
- With Dilute HCl: Forms aluminium chloride:
2Al(s)+6HCl(aq)→2AlCl3(aq)+3H2(g)
Aluminium Oxide (Al₂O₃)
- With NaOH: Dissolves to form sodium aluminate:
Al2O3(s)+2NaOH(aq)+3H2O(l)→2NaAl(OH)4(aq)
- With Dilute HCl: Forms aluminium chloride:
Al2O3(s)+6HCl(aq)→2AlCl3(aq)+3H2O(l)
Aluminium Hydroxide (Al(OH)₃)
- With NaOH: Dissolves to form sodium aluminate:
Al(OH)3(s)+NaOH(aq)→NaAl(OH)4(aq)
- With Dilute HCl: Forms aluminium chloride:
Al(OH)3(s)+3HCl(aq)→AlCl3(aq)+3H2O(l)
2. Zinc (Zn)
Zinc Metal
- With NaOH: Reacts in hot, concentrated NaOH to form sodium zincate:
Zn(s)+2NaOH(aq)+2H2O(l)→Na2Zn(OH)4(aq)+H2(g)
- With Dilute HCl: Forms zinc chloride:
Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g)
Zinc Oxide (ZnO)
- With NaOH: Forms sodium zincate:
ZnO(s)+2NaOH(aq)+H2O(l)→Na2Zn(OH)4(aq)
- With Dilute HCl: Forms zinc chloride:
ZnO(s)+2HCl(aq)→ZnCl2(aq)+H2O(l)
Zinc Hydroxide (Zn(OH)₂)
- With NaOH: Dissolves to form sodium zincate:
Zn(OH)2(s)+2NaOH(aq)→Na2Zn(OH)4(aq)
- With Dilute HCl: Forms zinc chloride:
Zn(OH)2(s)+2HCl(aq)→ZnCl2(aq)+2H2O(l)
3. Lead (Pb)
Lead Metal
- With NaOH: Does not react significantly under standard conditions.
- With Dilute HCl: Reacts slowly due to insoluble PbCl₂ formation:
Pb(s)+2HCl(aq)→PbCl2(s)+H2(g)
Lead(II) Oxide (PbO)
- With NaOH: Forms sodium plumbite:
PbO(s)+2NaOH(aq)+H2O(l)→Na2Pb(OH)4(aq)
- With Dilute HCl: Forms lead(II) chloride (sparingly soluble):
PbO(s)+2HCl(aq)→PbCl2(s)+H2O(l)
Lead(II) Hydroxide (Pb(OH)₂)
- With NaOH: Dissolves to form sodium plumbite:
Pb(OH)2(s)+2NaOH(aq)→Na2Pb(OH)4(aq)
- With Dilute HCl: Forms lead(II) chloride:
Pb(OH)2(s)+2HCl(aq)→PbCl2(s)+2H2O(l)
No comments:
Post a Comment