In this video we discuss - Vehicle turning on a horizontal circular track. We understand how friction of the road contributes to the centripetal force.
We also derive the equation - v(max)= sqrt(μrg).
Basically we answer the below questions:
*When a vehicle is taking a turn on horizontal road - the necessary centripetal force is provided by whom?
*At what maximum speed can a car safely negotiate a horizontal unbanked turn?
*What force causes centripetal acceleration of a car making a turn on a flat road?
*What type of force is responsible for keeping a car from skidding while moving around an unbanked curve?
No comments:
Post a Comment