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Vehicle turning on unbanked curve | Maximum velocity around an unbanked curve | Derivation of v(max)= sqrt(μrg)

 In this video we discuss - Vehicle turning on a horizontal circular track. We understand how friction of the road contributes to the centripetal force.

We also derive the equation - v(max)= sqrt(μrg).

Basically we answer the below questions:

 *When a vehicle is taking a turn on horizontal road - the necessary centripetal force is provided by whom? 

*At what maximum speed can a car safely negotiate a horizontal unbanked turn?

 *What force causes centripetal acceleration of a car making a turn on a flat road? 

*What type of force is responsible for keeping a car from skidding while moving around an unbanked curve? 

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